C++ Structures | Find output programs | Set 1

Answer Program 1:

Output:

0 2

Explanation:

Here, we created a structure that contains two integer variables. Here, we used NULL, EOF, and abs() function for initialization of structure elements.

The values of NULL and EOF are 0 and -1 respectively. And the function abs() returns positive value always.

A = NULL; //that is 0 
A = 0;
	
B = abs(EOF+EOF);
	= abs(-1+-1);
	= abs(-1-1);
	= abs(-2);
	= 2;

Then, the final value 0 and 2 will be printed on the console screen.

Answer Program 2:

Output:

main.cpp: In function ‘int main()’:
main.cpp:11:14: error: expected primary-expression before ‘.’ token
     cout << S.A << " " << S.B;
              ^
main.cpp:11:28: error: expected primary-expression before ‘.’ token
     cout << S.A << " " << S.B;
                            ^

Explanation:

Here, we created a structure using typedef that contains two integer variables A and B. Consider the below statement,

cout <<S.A<<" "<<S.B;

Here, we accessed A using S. but S is not an object or variable of structure, we used typedef it means S is type, so we need to create an object of structure using S like, S ob;

Then, ob.A and ob.B will be the proper way to access A and B.

Answer Program 3:

Output:

10 india

Explanation:

Here, we created a structure with two members A and STR. In the main() function, we created the object that is ob, and  a pointer ptr and then assigned the address of ob to ptr. Accessing the elements using referential operator -> and then printed them on the console screen.

The final output "10 india" will be printed on the console screen.