C++ goto Statement | Find output programs | Set 1

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Answer Program 1:

Output:

1 4 9 16 25

Explanation:

The above code will print "1 4 9 16 25" on the console screen.

Understand the program step by step.

Here we initialize the variables num1 and num2 by 1, 0 respectively.  And we created a label MY_LABEL.

Now evaluate statements iteration wise:

First iteration:

num1=1, num2=0
num2 = num1 * num1;
Then num1 = 1 and num2 = 1 and then print num2 that is 1.
As we know that if we calculate the 
zero power of any number that will be 1.
num1 = num1 + pow(2,0);
Then the above statement will increase the value of num1 by one. 
Then num1 become 2. 
And num1 is less than equal to 5 then "goto" statement 
will transfer the program control to the MY_LABEL.

Second iteration:

num1=2, num2=0
num2 = num1 * num1;
After execution of above statement, 
num1=2 and num2=4 and then print num2 that is 4
num1 = num1 + pow(2,0);
Then above statement will increase the value of num1 by one. 
Then num1 become 3. 
And num1 is less then equal to 5 then "goto” statement 
will transfer the program control to the MY_LABEL.

Third Generation:

num1=3, num2=0
num2 = num1 * num1;
After execution of above statement, 
num1=3 and num2=9 and then print num2 that is 9
num1 = num1 + pow(2,0);
Then above statement will increase the value of num1 by one. 
Then num1 become 4. 
And num1 is less then equal to 5 then "goto" statement 
will transfer the program control to the MY_LABEL.

Fourth iteration:

num1=3, num2=0
num2 = num1 * num1;
After execution of above statement, 
num1=4 and num2=16 and then print num2 that is 16
num1 = num1 + pow(2,0);
Then above statement will increase the value of num1 by one. 
Then num1 become 5. 
And num1 is less then equal to 5 then "goto" statement 
will transfer the program control to the MY_LABEL.

Fifth iteration:

num1=3, num2=0
num2 = num1 * num1;
After execution of above statement, 
num1=5 and num2=25 and then print num2 that is 25
num1 = num1 + pow(2,0);
Then above statement will increase the value of num1 by one. 
Then num1 become 6. 
Then condition get false and program get terminated.

Answer Program 2:

Output:

1 2 4 7

Explanation:

The above code will print "1 2 4 7" on the console screen.

Understand the program step by step.

Here we initialize the variables num1, num2, and num3 by 1, 0, and 1 respectively.  And we created a label MY_LABEL.

Now evaluate statements iteration wise:

First iteration:

Here initial values of num1=1, num2 =0, and num3 =1 
after executing all statements "1" will be printed on 
console screen and modified value will be:

num1 = 2, num2 = 1, num3= 1;

If the condition is true then program control 
will be transferred to MY_LABEL.

Second iteration:

Here values of num1=2, num2 =1, and num3 =1 
after executing all statements "2" will be printed on 
console screen and modified value will be:
num1 = 3, num2 = 2, num3= 2;

If the condition is true then program control 
will be transferred to MY_LABEL.

Third iteration:

Here values of num1=3, num2 =2, and num3 =2 
after executing all statements "4" will be printed on 
console screen and modified value will be:
num1 = 4, num2 = 3, num3= 4;

If the condition is true then program control 
will be transferred to MY_LABEL.

Fourth iteration:

Here values of num1=4, num2 =3, and num3 =4 
after executing all statements "7” will be printed on 
console screen and modified value will be:
num1 = 4, num2 = 4, num3= 7;

Now the if condition gets false and the program will terminate.

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