Q:

Java program to create a singly linked list of n nodes and count the number of nodes

belongs to collection: Java Singly Linked List Programs

robaa
Save to bookmark
|
2022-11-12
|
  226 
0

In this program, we need to create a singly linked list and count the nodes present in the list.

To accomplish this task, traverse through the list using node current which initially points to head. Increment current in such a way that current will point to its next node in each iteration and increment variable count by 1. In the end, the count will hold the value which denotes the number of nodes present in the list.

Algorithm

  • Create a class Node which has two attributes: data and next. Next is a pointer to the next node in the list.
  • Create another class which has two attributes: head and tail.
  • addNode() will add a new node to the list:
    • Create a new node.
    • It first checks, whether the head is equal to null which means the list is empty.
    • If the list is empty, both head and tail will point to the newly added node.
    • If the list is not empty, the new node will be added to end of the list such that tail's next will point to a newly added node. This new node will become the new tail of the list.

a. countNodes() will count the nodes present in the list:

  • Define a node current which will initially point to the head of the list.
  • Declare and initialize a variable count to 0.
  • Traverse through the list till current point to null.
  • Increment the value of count by 1 for each node encountered in the list.

a. display() will display the nodes present in the list:

  • Define a node current which will initially point to the head of the list.
  • Traverse through the list till current points to null.
  • Display each node by making current to point to node next to it in each iteration.
Java programming, examples, Java programming examples,
login and add your own answer to this question

All Answers

robaa
2022-11-12
need an explanation for this answer? contact us directly to get an explanation for this answer

Program:

public class CountNodes {    
        
    //Represent a node of singly linked list    
    class Node{    
        int data;    
        Node next;    
            
        public Node(int data) {    
            this.data = data;    
            this.next = null;    
        }    
    }    
     
    //Represent the head and tail of the singly linked list    
    public Node head = null;    
    public Node tail = null;    
        
    //addNode() will add a new node to the list    
    public void addNode(int data) {    
        //Create a new node    
        Node newNode = new Node(data);    
            
        //Checks if the list is empty    
        if(head == null) {    
            //If list is empty, both head and tail will point to new node    
            head = newNode;    
            tail = newNode;    
        }    
        else {    
            //newNode will be added after tail such that tail's next will point to newNode    
            tail.next = newNode;    
            //newNode will become new tail of the list    
            tail = newNode;    
        }    
    }    
        
    //countNodes() will count the nodes present in the list    
    public int countNodes() {    
        int count = 0;    
        //Node current will point to head    
        Node current = head;    
            
        while(current != null) {    
            //Increment the count by 1 for each node    
            count++;    
            current = current.next;    
        }    
        return count;    
    }    
            
    //display() will display all the nodes present in the list    
    public void display() {    
        //Node current will point to head    
        Node current = head;    
        if(head == null) {    
            System.out.println("List is empty");    
            return;    
        }    
        System.out.println("Nodes of singly linked list: ");    
        while(current != null) {    
            //Prints each node by incrementing pointer    
            System.out.print(current.data + " ");    
            current = current.next;    
        }    
        System.out.println();    
    }    
        
    public static void main(String[] args) {    
            
        CountNodes sList = new CountNodes();    
            
        //Add nodes to the list    
        sList.addNode(1);    
        sList.addNode(2);    
        sList.addNode(3);    
        sList.addNode(4);    
            
        //Displays the nodes present in the list    
        sList.display();    
            
        //Counts the nodes present in the given list    
        System.out.println("Count of nodes present in the list: " + sList.countNodes());    
    }    
}

Output:

Nodes of the singly linked list:
1 2 3 4 
Count of nodes present in the list: 4

need an explanation for this answer? contact us directly to get an explanation for this answer

total answers (1)

Java Singly Linked List Programs
This question belongs to these collections

Similar questions

need a help?

find thousands of online teachers now
Java program to create a singly linked list of n n... >>
<< Java Program to create and display a singly linked...