C Program For Denomination of an Amount Using While Loop

Denomination For USA Dollar

#include<stdio.h> 
int main() 
{ 
  int amt, r100=0, r50=0, r20=0, r10=0, r5=0, r2=0 , r1=0 ,count=0; 

  printf("Enter The Amount in Dollar : \n\n") ; 
  scanf("%d", &amt) ; 

  while(amt >= 100) 
  { 
    r100 = amt / 100 ; 
    amt = amt % 100;
    printf("\nTotal Number Of 100 Dollar : %d", r100) ;
    break ; 
  } 
  while(amt >= 50) 
  { 
    r50 = amt / 50 ;
    amt = amt % 50; 
    printf("\nTotal Number Of 50 Dollar : %d", r50) ; 
  break ; 
  }  
  while(amt >= 20) 
  { 
    r20 = amt / 20 ; 
    amt = amt % 20;
    printf("\nTotal Number Of 20 Dollar : %d", r20) ; 
    break ; 
  }  
  while(amt >= 10) 
  { 
    r10 = amt / 10 ; 
    amt = amt % 10;
    printf("\nTotal Number Of 10 Dollar Or Coin : %d", r10) ; 
    break ; 
  } 
  while(amt >= 5) 
  { 
    r5 = amt / 5 ; 
    amt = amt % 5;
    printf("\nTotal Number Of 5 Dollar Or Coin : %d", r5) ; 
    break ; 
  } 
  while(amt >= 2) 
  { 
    r2 = amt / 2 ; 
    amt = amt % 2;
    printf("\nTotal Number Of 2 Dollar Or Coin : %d", r2) ; 
    break ; 
  } 
  while(amt >= 1) 
  { 
    r1 = amt / 1 ; 
    amt = amt % 1;
    printf("\nTotal Number Of 1 Dollar Or Coin : %d", r1) ; 
    break ; 
  }
 count = r100 + r50 + r20 + r10 + r5 + r2 + r1;   
  printf("\n\nTotal Number Of Dollar Require : %d\n", count) ; 
 return 0;  
}

Output:

Enter The Amount in Dollar :

12345

Total Number Of 100 Dollar : 123

Total Number Of 20 Dollar : 2

Total Number Of 5 Dollar Or Coin : 1

Total Number Of Dollar Require : 126

 Denomination For Indian Rupees

#include<stdio.h> 
int main() 
{ 
  int amt, r2000=0, r500=0, r100=0, r50=0, r20=0, r10=0, r5=0, r2=0 , r1=0 ,count=0; 
  printf("Enter The Amount in Rupees : \n\n") ; 
  scanf("%d", &amt) ; 
  
 while(amt >= 2000) 
  { 
    r2000 = amt / 2000 ; 
    amt = amt % 2000;
    printf("\nTotal Number Of 2000 Rupees Notes : %d", r2000) ;
    break ; 
  }
 while(amt >= 500) 
  { 
    r500 = amt / 500 ; 
    amt = amt % 500;
    printf("\nTotal Number Of 500 Rupees Notes : %d", r500) ;
    break ; 
  } 
  while(amt >= 100) 
  { 
    r100 = amt / 100 ; 
    amt = amt % 100;
    printf("\nTotal Number Of 100 Rupees Notes : %d", r100) ;
    break ; 
  } 
  while(amt >= 50) 
  { 
    r50 = amt / 50 ;
    amt = amt % 50; 
    printf("\nTotal Number Of 50 Rupees Notes : %d", r50) ; 
  break ; 
  }  
  while(amt >= 20) 
  { 
    r20 = amt / 20 ; 
    amt = amt % 20;
    printf("\nTotal Number Of 20 Rupees Notes : %d", r20) ; 
    break ; 
  }  
  while(amt >= 10) 
  { 
    r10 = amt / 10 ; 
    amt = amt % 10;
    printf("\nTotal Number Of 10 Rupees Notes Or Coin : %d", r10) ; 
    break ; 
  } 
  while(amt >= 5) 
  { 
    r5 = amt / 5 ; 
    amt = amt % 5;
    printf("\nTotal Number Of 5 Rupees Notes Or Coin : %d", r5) ; 
    break ; 
  } 
  while(amt >= 2) 
  { 
    r2 = amt / 2 ; 
    amt = amt % 2;
    printf("\nTotal Number Of 2 Rupees Notes Or Coin : %d", r2) ; 
    break ; 
  } 
  while(amt >= 1) 
  { 
    r1 = amt / 1 ; 
    amt = amt % 1;
    printf("\nTotal Number Of 1 Rupees Note Or Coin : %d", r1) ; 
    break ; 
  }
 count = r2000 + r500 + r100 + r50 + r20 + r10 + r5 + r2 + r1;   
  printf("\n\nTotal Number Of Notes Require : %d\n", count) ; 
 return 0;  
}

Output:

Enter The Amount in Rupees : 

56691

Total Number Of 2000 Rupees Notes : 28

Total Number Of 500 Rupees Notes : 1

Total Number Of 100 Rupees Notes : 1

Total Number Of 50 Rupees Notes : 1

Total Number Of 20 Rupees Notes : 2

Total Number Of 1 Rupees Note Or Coin : 1

Total Number Of Notes Require : 34