Given a range 1 to N. Among its different permutations you have to find out those permutations where only one element is greater than its previous element and you have to count that number
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Let the range is N. Therefore, the numbers are X1, X2, X3, ..., XN.
Let f(i) = select an element in the permutation.
To know which elements are already visited in the array we will use a Boolean array and store the permutations we will use another array.
To find out the permutations we will follow these following steps,
C++ Implementation:
Output
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