Write a Java program to that reads a date (from 2004/1/1 to 2004/12/31) and prints the day of the date. Jan. 1, 2004, is Thursday. Note that 2004 is a leap year.

Code:

import java.util.*;
 
class Main {
 
    static int days[] = {31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    static String name[] = {"Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday"};
 
    public static void main(String args[]){
        Scanner in = new Scanner(System.in);
		System.out.println("Input month and date(o o to exit)");
		
        for(;;){
            int m=in.nextInt(), d=in.nextInt();
            if(m==0&&d==0) break;
            System.out.println(solve(m,d));
        }
    }
 
    static String solve(int month, int date){
        int cur = 3;
		System.out.println("Name of the day:");
        for(int i=0; i<month-1; i++) cur += days[i];
        cur += date-1;
        return name[cur%7];
    }
 
}