Q:

By implication, a variable that uses auto as its type specifier must have an initializer

KasimKamal
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2022-07-03
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By implication, a variable that uses auto as its type specifier must have an initializer.

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KasimKamal
2022-07-03
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// the type of item is deduced from the type of the result of adding val1 and val2
auto item = val1 + val2; // item initialized to the result of val1 + val2

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