Among the operations that don’t change the value of an object is initialization— when we use an object to initialize another object, it doesn’t matter whether either or both of the objects are consts

belongs to book: C++ Primer|Stanley B.Lippman, Josee Lajoie, Barbara E.Moo|5th Edition| Chapter number:2| Question number:e.g2.4.4

KasimKamal

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2022-07-03

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Among the operations that don’t change the value of an object is initialization— when we use an object to initialize another object, it doesn’t matter whether either or both of the objects are consts.

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KasimKamal

2022-07-03

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int i = 42;
const int ci = i; // ok: the value in i is copied into ci
int j = ci; // ok: the value in ci is copied into j

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Among the operations that don’t change the value of an object is initialization— when we use an object to initialize another object, it doesn’t matter whether either or both of the objects are consts

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