Q:

Golang program to get the size of structure using Sizeof() operator

belongs to collection: Golang Structure Programs

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In this program, we will create a structure and get the size of the structure using the Sizeof() operator and print the result on the console screen.

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Program/Source Code:

The source code to get the size of the structure using the Sizeof() operator is given below. The given program is compiled and executed successfully.

// Golang program to get the size of structure
// using Sizeof() operator

package main

import "fmt"
import "unsafe"

// Declaration of structure
type Sample struct {
	num1 int
	num2 int
	num3 int
}

func main() {
	obj := Sample{num1: 101, num2: 102, num3: 103}

	fmt.Println("Structure information: \n", obj)
	fmt.Println("\nSize of Structure: ", unsafe.Sizeof(obj))
}

Output:

Structure information:
 {101 102 103}

Size of Structure:  24

Explanation:

In the above program, we declare the package main. The main package is used to tell the Go language compiler that the package must be compiled and produced the executable file. Here, we imported the fmt package that includes the files of package fmt then we can use a function related to the fmt package.

In this program, we created a structure Sample, which is given below:

// Declaration of structure
type Sample struct { 
    num1 int 
    num2 int
    num3 int
} 

Here, we created the main() function. The main() function is the entry point for the program.

    obj := Sample{num1: 101,num2: 102,num3: 103}
    
    fmt.Println("Structure information: \n",obj)
    fmt.Println("\nSize of Structure: ", unsafe.Sizeof(obj))

In the above code, we initialized the sample object. After that, we calculated the size of the structure's object and print the result on the console screen.

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