Write a program in c to find the leap year

Algorithm:-

·        start

·        year

·        if(year%4==0) then  leap year

·        else not leap year

·        stop

     Flowchart:

Program:

#include<stdio.h>
#include<conio.h>
int main()
{
int year;
clrscr();
printf("enter the year :");
scanf("%d",&year);

if(year%4==0)
{
printf("the year %d is leap year",year);
}
else
{
printf("the year %d is not leap year",year);
}

return 0;

}

Output:

Enter a year: 2022
2022 is not a leap year.