Q:

What is the output of the below C code?

YasminRadwan26

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2022-06-24

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What is the output of the below C code?

#include <stdio.h>
int main(void)
{
    int var;
    for(var = -3 ; var <sizeof(int) ; var++)
    {
        printf("Hello Aticleworld\n");
    }
    return 0;
}

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YasminRadwan26

2022-06-24

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Output:

Nothing will print.

Explanation: In the above C code, We are trying to compare a signed int variable “var” with size_t, which is defined as an unsigned long int (sizeof operator return size_t). Here integer promotion occurs and the compiler will convert signed int -3 to unsigned long int and resultant value would very large as compare to int size. So the for loop condition will be false and there won’t be any iteration.

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