Are the expressions *++ptr and ++*ptr same?

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YasminRadwan26

2022-06-23

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Answer:

Both expressions are different. Let’s see a sample code to understand the difference between both expressions.

#include <stdio.h>
int main(void)
{
    int aiData[5] = {100,200,30,40,50};
    int *piData = aiData;
    ++*piData;
    printf("aiData[0] = %d, aiData[1] = %d, *piData = %d", aiData[0], aiData[1], *piData);
    return 0;
}

Output: 101 , 200 , 101

Explanation:
In the above example, two operators are involved and both have the same precedence with a right to left associativity. So the above expression ++*p is equivalent to ++ (*p). In other words, we can say it is pre-increment of value and output is 101, 200, 101.

#include <stdio.h>
int main(void)
{
    int aiData[5] = {100,200,30,40,50};
    int *piData = aiData;
    *++piData;
    printf("aiData[0] = %d, aiData[1] = %d, *piData = %d", aiData[0], aiData[1], *piData);
    return 0;
}

Output: 100, 200, 200

Explanation:
In the above example, two operators are involved and both have the same precedence with the right to left associativity. So the above expression *++p is equivalent to *(++p). In other words, you can say it is pre-increment of address and output is 100, 200,200.

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Are the expressions ++ptr and ++ptr same?

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