Program/Source Code:

The source code to swap two bits of a 32-bit integer number is given below. The given program is compiled and executed successfully.

// Java program to swap two bits of a 
// 32-bit integer number

import java.util.Scanner;

public class Main {
  public static void main(String[] args) {
    Scanner SC = new Scanner(System.in);

    int num = 0;
    int pos1 = 0;
    int pos2 = 0;

    int i = 0;

    System.out.printf("Enter Number: ");
    num = SC.nextInt();

    System.out.printf("Enter position1: ");
    pos1 = SC.nextInt();

    System.out.printf("Enter position2: ");
    pos2 = SC.nextInt();

    System.out.printf("Binary number before swapping bits: \n");

    for (i = 31; i >= 0; i--) {
      if ((num & (1 << i)) != 0)
        System.out.printf("1");
      else
        System.out.printf("0");
    }

    if ((((num & (1 << pos1)) >> pos1) ^ ((num & (1 << pos2)) >> pos2)) != 0) {
      num ^= (1 << pos1);
      num ^= (1 << pos2);
    }

    System.out.printf("\nResult is: %d\n", num);
    System.out.printf("Binary number after swapping bits: \n");

    for (i = 31; i >= 0; i--) {
      if ((num & (1 << i)) != 0)
        System.out.printf("1");
      else
        System.out.printf("0");
    }
    System.out.printf("\n");
  }
}

Output:

Enter Number: 2730
Enter position1: 1
Enter position2: 2
Binary number before swapping bits: 
00000000000000000000101010101010
Result is: 2732
Binary number after swapping bits: 
00000000000000000000101010101100