Program/Source Code:

The source code to check a number containing the alternative pattern of bits is given below. The given program is compiled and executed successfully.

// Java program to check a number that contains 
// the alternative pattern of bits

import java.util.Scanner;

public class Main {
  public static void main(String[] args) {
    Scanner SC = new Scanner(System.in);

    int num = 0;
    int tmp = 0;
    int cnt = 0;
    int i = 0;

    System.out.printf("Enter number: ");
    num = SC.nextInt();

    tmp = num;
    while (tmp != 0) {
      cnt++;
      tmp = tmp >> 1;
    }

    System.out.printf("Binary Number: ");
    for (i = cnt - 1; i >= 0; i--) {
      if ((num & (1 << i)) != 0)
        System.out.printf("1");
      else
        System.out.printf("0");
    }

    for (i = 0; i < cnt - 1; i++) {
      if (((num >> i) & 1) == ((num >> (i + 2)) & 1)) {
        continue;
      } else {
        System.out.printf("\nAlternate BIT pattern does not exist\n");
        return;
      }
    }
    System.out.printf("\nAlternate BIT pattern exists\n");
  }
}

Output:

Enter number: 170
Binary Number: 10101010
Alternate BIT pattern exists