Python program to record similar tuple occurrence

Method 1:

One method to solve the problem is by creating s dictionary that contains the occurrence count of the tuple. For this, we will iterate over the list which is a sorted form, and use a counter to count distinct occurrences. Then return the distinct value dictionary.

# Python program to record similar tuple 
# occurrence using Counter 

from collections import Counter

# Initializing and printing list to tuples
tupList = [(9, 5), (0, 2), (3, 3), (9, 5), (3, 3)]
print("The elements of list of tuples is " + str(tupList))

# Recording similar tuple occurrence
similarDict = dict(Counter(tuple(val) for val in map(sorted, tupList)))

# Printing result
print("The occurrence count of each tuple in list is " + str(similarDict))

Output:

The elements of list of tuples is [(9, 5), (0, 2), (3, 3), (9, 5), (3, 3)]
The occurrence count of each tuple in list is {(5, 9): 2, (0, 2): 1, (3, 3): 2}

Method 2:

Another approach includes the use of frozenset() method that orders the tuple. This makes sure that the counting done using the counter() method is more effective.

# Python program to record similar 
# tuple occurrence 

from collections import Counter

# Initializing and printing list to tuples
tupList = [(9, 5), (0, 2), (3, 3), (9, 5), (3, 3)]
print("The elements of list of tuples is " + str(tupList))

# Recording similar tuple occurrence
similarDict = dict(Counter(tuple(frozenset(tup)) for tup in tupList))

# Printing result
print("The occurrence count of each tuple in list is " + str(similarDict))

Output:

The elements of list of tuples is [(9, 5), (0, 2), (3, 3), (9, 5), (3, 3)]
The occurrence count of each tuple in list is {(9, 5): 2, (0, 2): 1, (3,): 2}