Python program to chunk tuples to N size

Method 1:

One method to solve the problem is by using a direct method. In which, we will iterate the tuple and use another count for size N values to be feeding in new chunk tuples.

# Initializing and printing the tuple 
# and chunk size 

myTup =(4, 2, 7, 6, 1, 12, 54, 76, 87, 99)

print("The elements of tuple are " + str(myTup))

N = 2
print("The chunk size(N) is " + str(N))

# Chunking tuples to N
chunkTup = [myTup[i : i + N] for i in range(0, len(myTup), N)]

print("The list of chunk tuples of size N is " + str(chunkTup))

Output:

The elements of tuple are (4, 2, 7, 6, 1, 12, 54, 76, 87, 99)
The chunk size(N) is 2
The list of chunk tuples of size N is [(4, 2), (7, 6), (1, 12), (54, 76), (87, 99)]

Method 2:

Another approach to solving the problem is by using iter() method to create an iterator of size N, which then we converted into tuple using zip() method.

# Initializing and printing the tuple 
# and chunk size

myTup =(4, 2, 7, 6, 1, 12, 54, 76, 87, 99)

print("The elements of tuple are " + str(myTup))

N = 2

print("The chunk size(N) is " + str(N))

# Chunking tuples to N
chunkTup = list(zip(*[iter(myTup)] * N))

print("The list of chunk tuples of size N is " + str(chunkTup))

Output:

The elements of tuple are (4, 2, 7, 6, 1, 12, 54, 76, 87, 99)
The chunk size(N) is 2
The list of chunk tuples of size N is [(4, 2), (7, 6), (1, 12), (54, 76), (87, 99)]