Python program to alternate elements operation on tuple

Method 1:

One method is to simply loop over the tuple and find the elements that have an alternate occurrence index. For this, we will be using the enumerate() method and then alternate the elements using the conditional operator.

# Python program to Alternate Elements Operation
# on Tuple

# Creating and printing tuple list 
myTuple = (3, 1, 6, 4, 9)
print("Initial values of tuple : " + str(myTuple))

# Performing alternate element operation
sumEven = 0
sumOdd = 0
for idx, value in enumerate(myTuple):
	if idx % 2:
		sumEven += value
	else :
		sumOdd += value

# Printing alternate elements operation 
print("The alternate elements sum for even index values : " + str(sumEven))
print("The alternate elements sum for odd index values : " + str(sumOdd))

Output:

Initial values of tuple : (3, 1, 6, 4, 9)
The alternate elements sum for even index values : 5
The alternate elements sum for odd index values : 18

Method 2:

Another method to solve the problem is by using the slice operator which will extract the elements of the tuple from the required alternate index.

# Python program to Alternate Elements Operation
# on Tuple

# Creating and printing tuple list 
myTuple = (3, 1, 6, 4, 9)
print("Initial values of tuple : " + str(myTuple))

# Performing alternate element operation
sumOdd = sum(myTuple[1::2])
sumEven = sum(myTuple[0::2])
  
# Printing alternate elements operation 
print("The alternate elements sum for even index values : " + str(sumEven))
print("The alternate elements sum for odd index values : " + str(sumOdd))

Output:

Initial values of tuple : (3, 1, 6, 4, 9)
The alternate elements sum for even index values : 18
The alternate elements sum for odd index values : 5