Q:

Python program to perform cross tuple summation grouping using 2nd element

mahmoud2506
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2022-05-23
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Example:

tuple = ("python", "includehelp", 43, 54.23)

List is a sequence data type. It is mutable as its values in the list can be modified. It is a collection of an ordered set of values enclosed in square brackets []

Example:

list = [3 ,1,  5, 7]

Now, let's get back to our topic of cross tuple summation.

Cross Tuple Summation Grouping in Python

While creating complex applications we need to manipulate data structures a lot, one of which is a cross-collection summation in which we perform cross summation of collections based on the sum condition element.

Cross Tuple summation grouping is performing summation operation between tuples using a specific element of the tuple which in this problem is the 2nd element of the tuple. So, we will be adding the first elements of all tuples of the list whose second element is the same.

Input:
tupList = [(2, 3), (9, 3), (1, 5), (2, 8)]

Output:
[(11, 3), (1, 5), (2, 8)]

For solving such problems, python provides multiple ways and methods.

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All Answers

mahmoud2506
2022-05-23
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Method 1:

A direct method to solve the problem is by traversing the list and checking tuples with the same second element and performing addition based on it.

# Python program to perform cross tuple summation 

# Creating and printing the Tuple List 
tupList = [(2, 3), (9, 3), (1, 5), (2, 8)]
print("Initial Tuple List : " + str(tupList))

# cross tuple summing 
myDict = dict()
for val1, val2 in tupList:
	myDict[val2] = myDict.get(val2, 0) + val1
sumTuple = [(val2, val1) for (val1, val2) in myDict.items()]

# Printing summation list 
print(" List after cross Tuple summation : " + str(sumTuple))

Output:

Initial Tuple List : [(2, 3), (9, 3), (1, 5), (2, 8)]
 List after cross Tuple summation : [(11, 3), (1, 5), (2, 8)]

Method 2:

An Alternative method to solve the problem is by performing summation using sum() method along with list comprehension and checking for tuples with the same second value using groupby() method. Then create the list by using zip() method.

# Python program to perform cross tuple summation 

from itertools import groupby

# Creating and printing the Tuple List 
tupList = [(2, 3), (9, 3), (1, 5), (2, 8)]
print("Initial Tuple List : " + str(tupList))

# cross tuple summing 
sumTuple = [(sum(next(zip(*vals))), key) for key, vals in groupby(tupList, key = lambda tup:tup[1])]
  
# Printing summation list 
print(" List after cross Tuple summation : " + str(sumTuple))

Output:

Initial Tuple List : [(2, 3), (9, 3), (1, 5), (2, 8)]
 List after cross Tuple summation : [(11, 3), (1, 5), (2, 8)]

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