Q:

Python program to create a list of tuples from given list having number and its cube in each tuple

0

Example:

tuple = ("python", "includehelp", 43, 54.23)

Creating a list of tuples from given list having number and its cube in each tuple

We have a list of elements and we need to create another list of elements such that each element of the new list is a tuple. And each of the tuples consists of two values one the element from the list and the second will be the cube of the value.

Example:

Input: 
list = [4, 1, 6, 2]

Output: 
[(4, 64), (1, 1), (6, 216), (2, 8)]

We simply need to iterate over all the elements of the list and then for each element create a tuple consisting of the element and its cube and then append it to a list.

This can be done by simply loop and also to shorten the code we can use comprehension techniques. Here is a code depicting both the methods.

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Program:

# Creating a list
myList = [6, 2, 5 ,1, 4]

# Creating list of tuples 
tupleList = [] 
for val in myList:
    myTuple = (val, (val*val*val))
    tupleList.append(myTuple)

# print the result
print("The list of Tuples is " , str(tupleList))

Output:

The list of Tuples is  [(6, 216), (2, 8), (5, 125), (1, 1), (4, 64)]

Using comprehension

# Creating a list
myList = [6, 2, 5 ,1, 4]

# Creating list of tuples 
tupleList = [(val, (val*val*val)) for val in myList]

# print the result
print("The list of Tuples is " , str(tupleList))

Output:

The list of Tuples is  [(6, 216), (2, 8), (5, 125), (1, 1), (4, 64)]

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