Given a string that contains ternary expressions. The expressions may be nested. You need to convert the given ternary expression to a binary Tree and return the root
Given a string that contains ternary expressions. The expressions may be nested. You need to convert the given ternary expression to a binary Tree and return the root
Example:
Input:
a?b:c
Output:
a
/ \
b c
Input:
a?b?c:d:e
Output:
a
/ \
b e
/ \
c d
//recursive function to build the tree
FUNCTION convertExpression(string str, int& i)
1. Create root referring to the current character(str[i]);
root =newNode(str,i); //create a node with element str[i]
2. Increment i (index that point to current character);
//if i<string length and current token is '?' increment i
3. IF(i<str.length() && str[i]=='?'){
//need to build left child recursively increment i
root->left=convertExpression(str,i);
//need to build right child recursively
root->right=convertExpression(str,i);
4. return root;
Algorithm with example:
Tree nodes represented by their values only
Input string (ternary expression)
a?b:c
-------------------------------------------------
In main function we call convertExpression(str,0)
convertExpression(str,0):
root=newNode(str, 0); //root=a
i=1; //incremented
i<str.length() && str[i]=='?'
i=2;//incremented
root->left=convertExpression(str,2);
-------------------------------------------------
convertExpression(str,2):
root=newNode(str, 2); //root=b
i=3; //incremented
i<str.length()&& str[i]!='?'
return root //b
at convertExpression(str,0)
now root->left=b
i=4; //i++ step evaluated
root->right=convertExpression(str,4)
-------------------------------------------------
convertExpression(str,4):
root=newNode(str, 4); //root=c
i=5; //incremented
I is not <str.length()
return root //c
at convertExpression(str,0)
now root->right=c
return root;
returns to main
built tree:
a
/ \
b c
C++ implementation
#include <bits/stdc++.h>
using namespace std;
struct Node{
char data;
Node *left,*right;
};
//function to create node
Node *newNode(char Data)
{
Node *new_node = new Node;
new_node->data = Data;
new_node->left = new_node->right = NULL;
return new_node;
}
//function to traverse preorder
void preorder(Node *root){
if(root==NULL)
return;
cout<<root->data<<" ";
preorder(root->left);
preorder(root->right);
}
//recursive function to build the tree
Node *convertExpression(string str,int& i)
{
Node* root=newNode(str[i]);
i++;
if(i<str.length() && str[i]=='?'){
i++;
root->left=convertExpression(str,i);
i++; //skipping ':' character
root->right=convertExpression(str,i);
}
return root;
}
int main(){
string str;
cout<<"Enter your expression\n";
cin>>str;
int i=0;
Node *root=convertExpression(str,i);
cout<<"Printing pre-order traversal of the tree...\n";
//pre-order traversal of the tree,
//should be same with expressionthe
preorder(root);
cout<<endl;
return 0;
}
Output
First run:
Enter your expression
a?b:c
Printing pre-order traversal of the tree...
a b c
Second run:
Enter your expression
a?b?c:e:d
Printing pre-order traversal of the tree...
a b c e d
Algorithm:
Algorithm with example:
C++ implementation
Output
need an explanation for this answer? contact us directly to get an explanation for this answer