Linear search in C to find whether a number is present in an array. If it's present, then at what location it occurs. It is also known as a sequential search. It is straightforward and works as follows: we compare each element with the element to search until we find it or the list ends
#include <stdio.h>
int main()
{
int array[100], search, c, n;
printf("Enter number of elements in array\n");
scanf("%d", &n);
printf("Enter %d integer(s)\n", n);
for (c = 0; c < n; c++)
scanf("%d", &array[c]);
printf("Enter a number to search\n");
scanf("%d", &search);
for (c = 0; c < n; c++)
{
if (array[c] == search) /* If required element is found */
{
printf("%d is present at location %d.\n", search, c+1);
break;
}
}
if (c == n)
printf("%d isn't present in the array.\n", search);
return 0;
}
C programming
output:
Enter number of elements in array
3
Enter 3 integer(s)
1
2
3
Enter a number to search
3
3 is present at location 3.
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