Write a postgre SQL subquery to find the employee ID, first name, last name and salary of all employees whose salary is above the average salary for their departments
Write a postgre SQL subquery to find the employee ID, first name, last name and salary of all employees whose salary is above the average salary for their departments.
pg_exercises=# SELECT employee_id, first_name
pg_exercises-# FROM employees AS A
pg_exercises-# WHERE salary >
pg_exercises-# ( SELECT AVG(salary)
pg_exercises(# FROM employees
pg_exercises(# WHERE department_id = A.department_id);
employee_id | first_name
-------------+------------
103 | Alexander
104 | Bruce
114 | Den
100 | Steven
141 | Trenna
156 | Janette
157 | Patrick
158 | Allan
162 | Clara
122 | Payam
123 | Shanta
124 | Kevin
137 | Renske
174 | Ellen
145 | John
146 | Karen
147 | Alberto
148 | Gerald
149 | Eleni
150 | Peter
151 | David
184 | Nandita
185 | Alexis
188 | Kelly
152 | Peter
189 | Jennifer
192 | Sarah
193 | Britney
120 | Matthew
121 | Adam
108 | Nancy
109 | Daniel
168 | Lisa
169 | Harrison
170 | Tayler
201 | Michael
205 | Shelley
(37 rows)
Sample table: employees
Output:
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