Write a PL/SQL program to display the name of the employee and increment percentage of salary according to their working experiences

DROP TABLE emp_temp;
CREATE TABLE emp_temp AS
  SELECT *
  FROM employees;
 
 
DECLARE
  CURSOR employees_cur IS
    SELECT employee_id,
           first_name,
           Trunc(Months_between(SYSDATE,hire_date) / 12) expr
    FROM   emp_temp;

incre_per NUMBER(2);
BEGIN
  dbms_output.put_line(rpad('Employee ID',15)||rpad('Name',25) || 'Increment %');
  dbms_output.Put_line('-----------------------------------------------------------');
  FOR store_emp_rec IN employees_cur 
  LOOP
    incre_per :=
    CASE
    WHEN store_emp_rec.expr > 10 THEN
      15
    WHEN store_emp_rec.expr > 5 THEN
      10
    ELSE
      8
    END;
    UPDATE emp_temp
    SET    salary = salary + (salary * incre_per / 100)
    WHERE  employee_id = store_emp_rec.employee_id;
dbms_output.put_line(rpad(store_emp_rec.employee_id,15) ||rpad(store_emp_rec.first_name,25)||  incre_per );	
  END LOOP;
END;
/