Q:

Write a query in SQL to list the name, salary, and commission for those employees whose net pay is greater than or equal to the salary of any other employee in the company

hamza
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2022-05-18
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Write a query in SQL to list the name, salary, and commission for those employees whose net pay is greater than or equal to the salary of any other employee in the company.

Sample table: employees

 emp_id | emp_name | job_name  | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+-----------+------------+------------+---------+------------+--------
  68319 | KAYLING  | PRESIDENT |            | 1991-11-18 | 6000.00 |            |   1001
  66928 | BLAZE    | MANAGER   |      68319 | 1991-05-01 | 2750.00 |            |   3001
  67832 | CLARE    | MANAGER   |      68319 | 1991-06-09 | 2550.00 |            |   1001
  65646 | JONAS    | MANAGER   |      68319 | 1991-04-02 | 2957.00 |            |   2001
  67858 | SCARLET  | ANALYST   |      65646 | 1997-04-19 | 3100.00 |            |   2001
  69062 | FRANK    | ANALYST   |      65646 | 1991-12-03 | 3100.00 |            |   2001
  63679 | SANDRINE | CLERK     |      69062 | 1990-12-18 |  900.00 |            |   2001
  64989 | ADELYN   | SALESMAN  |      66928 | 1991-02-20 | 1700.00 |     400.00 |   3001
  65271 | WADE     | SALESMAN  |      66928 | 1991-02-22 | 1350.00 |     600.00 |   3001
  66564 | MADDEN   | SALESMAN  |      66928 | 1991-09-28 | 1350.00 |    1500.00 |   3001
  68454 | TUCKER   | SALESMAN  |      66928 | 1991-09-08 | 1600.00 |       0.00 |   3001
  68736 | ADNRES   | CLERK     |      67858 | 1997-05-23 | 1200.00 |            |   2001
  69000 | JULIUS   | CLERK     |      66928 | 1991-12-03 | 1050.00 |            |   3001
  69324 | MARKER   | CLERK     |      67832 | 1992-01-23 | 1400.00 |            |   1001
(14 rows)
Sql programming,
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All Answers

hamza
2022-05-18
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SELECT e.emp_name,
       e.salary,
       e.commission
FROM employees e
WHERE
    (SELECT max(salary+commission)
     FROM employees) >= ANY
    (SELECT salary
     FROM employees);SELECT e.emp_name,
       e.salary,
       e.commission
FROM employees e
WHERE
    (SELECT max(salary+commission)
     FROM employees) >= ANY
    (SELECT salary
     FROM employees);

Sample Output:

 emp_name | salary  | commission
----------+---------+------------
 KAYLING  | 6000.00 |
 BLAZE    | 2750.00 |
 CLARE    | 2550.00 |
 JONAS    | 2957.00 |
 SCARLET  | 3100.00 |
 FRANK    | 3100.00 |
 SANDRINE |  900.00 |
 ADELYN   | 1700.00 |     400.00
 WADE     | 1350.00 |     600.00
 MADDEN   | 1350.00 |    1500.00
 TUCKER   | 1600.00 |       0.00
 ADNRES   | 1200.00 |
 JULIUS   | 1050.00 |
 MARKER   | 1400.00 |
(14 rows)

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