Q:

Write a query in SQL to find the name of the patients and the number of physicians they have taken appointment

hamza
Save to bookmark
|
2022-05-18
|
  158 
0

 Write a query in SQL to find the name of the patients and the number of physicians they have taken appointment.

Sample table: appointment

appointmentid |  patient  | prepnurse | physician |    start_dt_time    |     end_dt_time     | examinationroom
---------------+-----------+-----------+-----------+---------------------+---------------------+-----------------
      13216584 | 100000001 |       101 |         1 | 2008-04-24 10:00:00 | 2008-04-24 11:00:00 | A
      26548913 | 100000002 |       101 |         2 | 2008-04-24 10:00:00 | 2008-04-24 11:00:00 | B
      36549879 | 100000001 |       102 |         1 | 2008-04-25 10:00:00 | 2008-04-25 11:00:00 | A
      46846589 | 100000004 |       103 |         4 | 2008-04-25 10:00:00 | 2008-04-25 11:00:00 | B
      59871321 | 100000004 |           |         4 | 2008-04-26 10:00:00 | 2008-04-26 11:00:00 | C
      69879231 | 100000003 |       103 |         2 | 2008-04-26 11:00:00 | 2008-04-26 12:00:00 | C
      76983231 | 100000001 |           |         3 | 2008-04-26 12:00:00 | 2008-04-26 13:00:00 | C
      86213939 | 100000004 |       102 |         9 | 2008-04-27 10:00:00 | 2008-04-21 11:00:00 | A
      93216548 | 100000002 |       101 |         2 | 2008-04-27 10:00:00 | 2008-04-27 11:00:00 | B
    ssn    |       name        |      address       |  phone   | insuranceid | pcp
-----------+-------------------+--------------------+----------+-------------+-----
 100000001 | John Smith        | 42 Foobar Lane     | 555-0256 |    68476213 |   1
 100000002 | Grace Ritchie     | 37 Snafu Drive     | 555-0512 |    36546321 |   2
 100000003 | Random J. Patient | 101 Omgbbq Street  | 555-1204 |    65465421 |   2
 100000004 | Dennis Doe        | 1100 Foobaz Avenue | 555-2048 |    68421879 |   3
Sql programming,
login and add your own answer to this question

All Answers

hamza
2022-05-18
need an explanation for this answer? contact us directly to get an explanation for this answer 

SELECT p.name "Patient",
       count(t.patient) "Appointment for No. of Physicians"
FROM appointment t
JOIN patient p ON t.patient=p.ssn
GROUP BY p.name
HAVING count(t.patient)>=1;

Sample Output:

      Patient      | Appointment for No. of Physicians
-------------------+-----------------------------------
 Grace Ritchie     |                                 2
 John Smith        |                                 3
 Dennis Doe        |                                 3
 Random J. Patient |                                 1
(4 rows)

need an explanation for this answer? contact us directly to get an explanation for this answer

total answers (1)

Similar questions

need a help?

find thousands of online teachers now