Q:

From the following tables, create a view that shows all matches of customers with salesperson such that at least one customer in the city of customer served by a salesperson in the city of the salesperson

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 From the following tables, create a view that shows all matches of customers with salesperson such that at least one customer in the city of customer served by a salesperson in the city of the salesperson.

Sample table: customer

customer_id |   cust_name    |    city    | grade | salesman_id 
-------------+----------------+------------+-------+-------------
        3002 | Nick Rimando   | New York   |   100 |        5001
        3007 | Brad Davis     | New York   |   200 |        5001
        3005 | Graham Zusi    | California |   200 |        5002
        3008 | Julian Green   | London     |   300 |        5002
        3004 | Fabian Johnson | Paris      |   300 |        5006
        3009 | Geoff Cameron  | Berlin     |   100 |        5003
        3003 | Jozy Altidor   | Moscow     |   200 |        5007
        3001 | Brad Guzan     | London     |       |        5005
 salesman_id |    name    |   city   | commission 
-------------+------------+----------+------------
        5001 | James Hoog | New York |       0.15
        5002 | Nail Knite | Paris    |       0.13
        5005 | Pit Alex   | London   |       0.11
        5006 | Mc Lyon    | Paris    |       0.14
        5007 | Paul Adam  | Rome     |       0.13
        5003 | Lauson Hen | San Jose |       0.12

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CREATE VIEW citymatch(custcity, salescity)
AS SELECT DISTINCT a.city, b.city
FROM customer a, salesman b
WHERE a.salesman_id = b.salesman_id;

output:

sqlpractice=# SELECT *
sqlpractice-# FROM citymatch;
  custcity  | salescity
------------+-----------
 Seattle    | Paris
 Moscow     | Rome
 New York   | New York
 NC         |
 Paris      | Paris
 California | Paris
 Berlin     |
 London     | Paris
 London     | London
 Dallas     | New York
(10 rows)

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