Q:

From the following table, write a SQL query to find those salesperson and customer where more than one order executed

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 From the following table, write a SQL query to find those salesperson and customer where more than one order executed. Sort the result-set on 2nd field. Return ID, name.

Sample table: customer

customer_id |   cust_name    |    city    | grade | salesman_id 
-------------+----------------+------------+-------+-------------
        3002 | Nick Rimando   | New York   |   100 |        5001
        3007 | Brad Davis     | New York   |   200 |        5001
        3005 | Graham Zusi    | California |   200 |        5002
        3008 | Julian Green   | London     |   300 |        5002
        3004 | Fabian Johnson | Paris      |   300 |        5006
        3009 | Geoff Cameron  | Berlin     |   100 |        5003
        3003 | Jozy Altidor   | Moscow     |   200 |        5007
        3001 | Brad Guzan     | London     |       |        5005
salesman_id |    name    |   city   | commission 
-------------+------------+----------+------------
        5001 | James Hoog | New York |       0.15
        5002 | Nail Knite | Paris    |       0.13
        5005 | Pit Alex   | London   |       0.11
        5006 | Mc Lyon    | Paris    |       0.14
        5007 | Paul Adam  | Rome     |       0.13
        5003 | Lauson Hen | San Jose |       0.12
ord_no      purch_amt   ord_date    customer_id  salesman_id
----------  ----------  ----------  -----------  -----------
70001       150.5       2012-10-05  3005         5002
70009       270.65      2012-09-10  3001         5005
70002       65.26       2012-10-05  3002         5001
70004       110.5       2012-08-17  3009         5003
70007       948.5       2012-09-10  3005         5002
70005       2400.6      2012-07-27  3007         5001
70008       5760        2012-09-10  3002         5001
70010       1983.43     2012-10-10  3004         5006
70003       2480.4      2012-10-10  3009         5003
70012       250.45      2012-06-27  3008         5002
70011       75.29       2012-08-17  3003         5007
70013       3045.6      2012-04-25  3002         5001

All Answers

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SELECT customer_id as “ID”,  cust_name as “NAME”
	FROM customer a
	WHERE 1<
		(SELECT COUNT (*)
		   FROM orders b
		   WHERE a.customer_id = b.customer_id)
UNION
(SELECT salesman_idas “ID”,   nameas “NAME”
	FROM salesman a
	WHERE 1 <
		(SELECT COUNT (*)
		 FROM orders b
		WHERE  a.salesman_id = b.salesman_id))
ORDER BY 2

Sample Output:

ID	        NAME
3009		Geoff Cameron
3005		Graham Zusi
5001		James Hoog
5003		Lauson Hen
5002		Nail Knite
3002		Nick Rimando

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