Q:

From the following tables, write a SQL query to find all those customers who have different grade than any customer lives in Dallas City

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From the following tables, write a SQL query to find all those customers who have different grade than any customer lives in Dallas City. Return customer_id, cust_name,city, grade and salesman_id.

Sample table: Customer

 customer_id |   cust_name    |    city    | grade | salesman_id 
-------------+----------------+------------+-------+-------------
        3002 | Nick Rimando   | New York   |   100 |        5001
        3007 | Brad Davis     | New York   |   200 |        5001
        3005 | Graham Zusi    | California |   200 |        5002
        3008 | Julian Green   | London     |   300 |        5002
        3004 | Fabian Johnson | Paris      |   300 |        5006
        3009 | Geoff Cameron  | Berlin     |   100 |        5003
        3003 | Jozy Altidor   | Moscow     |   200 |        5007
        3001 | Brad Guzan     | London     |       |        5005

All Answers

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SELECT *
FROM customer 
WHERE NOT grade = ANY
   (SELECT grade
	FROM customer
	WHERE city='Dallas');

Output of the Query:

customer_id	cust_name		city		grade	salesman_id
3002		Nick Rimando		New York	100	5001
3007		Brad Davis		New York	200	5001
3005		Graham Zusi		California	200	5002
3008		Julian Green		London		300	5002
3004		Fabian Johnson		Paris		300	5006
3009		Geoff Cameron		Berlin		100	5003
3003		Jozy Altidor		Moscow		200	5007
3001		Brad Guzan		London			5005

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