Q:

From the following table, write a SQL query to find all those customers who have a greater grade than any customer who belongs to the alphabetically lower than the city

hamza
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2022-05-18
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 From the following table, write a SQL query to find all those customers who have a greater grade than any customer who belongs to the alphabetically lower than the city of New York. Return customer_id, cust_name, city, grade, salesman_id.

Sample table: Customer

 customer_id |   cust_name    |    city    | grade | salesman_id 
-------------+----------------+------------+-------+-------------
        3002 | Nick Rimando   | New York   |   100 |        5001
        3007 | Brad Davis     | New York   |   200 |        5001
        3005 | Graham Zusi    | California |   200 |        5002
        3008 | Julian Green   | London     |   300 |        5002
        3004 | Fabian Johnson | Paris      |   300 |        5006
        3009 | Geoff Cameron  | Berlin     |   100 |        5003
        3003 | Jozy Altidor   | Moscow     |   200 |        5007
        3001 | Brad Guzan     | London     |       |        5005
Sql programming,
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All Answers

hamza
2022-05-18
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SELECT *
FROM customer
WHERE grade > ANY
   (SELECT grade
	FROM CUSTOMER
	WHERE  city < 'New York');

Output of the Query:

customer_id	cust_name		city		grade	salesman_id
3007		Brad Davis		New York	200	5001
3005		Graham Zusi		California	200	5002
3008		Julian Green		London		300	5002
3004		Fabian Johnson		Paris		300	5006
3003		Jozy Altidor		Moscow		200	5007

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