Q:

From the following tables, write a SQL query to find all those salespeople whose name exist alphabetically after the customer’s name. Return salesman_id, name, city,

hamza
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2022-05-18
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From the following tables, write a SQL query to find all those salespeople whose name exist alphabetically after the customer’s name. Return salesman_id, name, city, commission.

Sample table: Salesman

salesman_id |    name    |   city   | commission 
-------------+------------+----------+------------
        5001 | James Hoog | New York |       0.15
        5002 | Nail Knite | Paris    |       0.13
        5005 | Pit Alex   | London   |       0.11
        5006 | Mc Lyon    | Paris    |       0.14
        5007 | Paul Adam  | Rome     |       0.13
        5003 | Lauson Hen | San Jose |       0.12
 customer_id |   cust_name    |    city    | grade | salesman_id 
-------------+----------------+------------+-------+-------------
        3002 | Nick Rimando   | New York   |   100 |        5001
        3007 | Brad Davis     | New York   |   200 |        5001
        3005 | Graham Zusi    | California |   200 |        5002
        3008 | Julian Green   | London     |   300 |        5002
        3004 | Fabian Johnson | Paris      |   300 |        5006
        3009 | Geoff Cameron  | Berlin     |   100 |        5003
        3003 | Jozy Altidor   | Moscow     |   200 |        5007
        3001 | Brad Guzan     | London     |       |        5005
Sql programming,
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hamza
2022-05-18
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SELECT *
FROM salesman a
WHERE EXISTS
   (SELECT *
	FROM CUSTOMER b
	WHERE  a.name  < b.cust_name);

Output of the Query:

salesman_id	name		city		commission
5001		James Hoog	New York	0.15
5002		Nail Knite	Paris		0.13
5006		Mc Lyon		Paris		0.14
5003		Lauson Hen	San Jose	0.12

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