Q:

From the following tables, write a SQL query to find the order values greater than the average order value of 10th October 2012

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From the following tables, write a SQL query to find the order values greater than the average order value of 10th October 2012. Return ord_no, purch_amt, ord_date, customer_id, salesman_id.

Sample table: Salesman

salesman_id |    name    |   city   | commission 
-------------+------------+----------+------------
        5001 | James Hoog | New York |       0.15
        5002 | Nail Knite | Paris    |       0.13
        5005 | Pit Alex   | London   |       0.11
        5006 | Mc Lyon    | Paris    |       0.14
        5007 | Paul Adam  | Rome     |       0.13
        5003 | Lauson Hen | San Jose |       0.12
ord_no      purch_amt   ord_date    customer_id  salesman_id
----------  ----------  ----------  -----------  -----------
70001       150.5       2012-10-05  3005         5002
70009       270.65      2012-09-10  3001         5005
70002       65.26       2012-10-05  3002         5001
70004       110.5       2012-08-17  3009         5003
70007       948.5       2012-09-10  3005         5002
70005       2400.6      2012-07-27  3007         5001
70008       5760        2012-09-10  3002         5001
70010       1983.43     2012-10-10  3004         5006
70003       2480.4      2012-10-10  3009         5003
70012       250.45      2012-06-27  3008         5002
70011       75.29       2012-08-17  3003         5007
70013       3045.6      2012-04-25  3002         5001

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SELECT *
FROM orders
WHERE purch_amt >
    (SELECT  AVG(purch_amt) 
     FROM orders 
     WHERE ord_date ='10/10/2012');

Output of the Query:

ord_no	purch_amt	ord_date	customer_id	salesman_id
70005	2400.60		2012-07-27	3007		5001
70008	5760.00		2012-09-10	3002		5001
70003	2480.40		2012-10-10	3009		5003
70013	3045.60		2012-04-25	3002		5001

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