Q:

Write a SQL statement to make a list for the salesmen who either work for one or more customers or yet to join any of the customer

hamza
Save to bookmark
|
2022-05-18
|
  139 
0

Write a SQL statement to make a list for the salesmen who either work for one or more customers or yet to join any of the customer. The customer, may have placed, either one or more orders on or above order amount 2000 and must have a grade, or he may not have placed any order to the associated supplier.

Sample table: customer

customer_id |   cust_name    |    city    | grade | salesman_id 
-------------+----------------+------------+-------+-------------
        3002 | Nick Rimando   | New York   |   100 |        5001
        3007 | Brad Davis     | New York   |   200 |        5001
        3005 | Graham Zusi    | California |   200 |        5002
        3008 | Julian Green   | London     |   300 |        5002
        3004 | Fabian Johnson | Paris      |   300 |        5006
        3009 | Geoff Cameron  | Berlin     |   100 |        5003
        3003 | Jozy Altidor   | Moscow     |   200 |        5007
        3001 | Brad Guzan     | London     |       |        5005
Sample table: salesman
salesman_id |    name    |   city   | commission 
-------------+------------+----------+------------
        5001 | James Hoog | New York |       0.15
        5002 | Nail Knite | Paris    |       0.13
        5005 | Pit Alex   | London   |       0.11
        5006 | Mc Lyon    | Paris    |       0.14
        5007 | Paul Adam  | Rome     |       0.13
        5003 | Lauson Hen | San Jose |       0.12
ord_no      purch_amt   ord_date    customer_id  salesman_id
----------  ----------  ----------  -----------  -----------
70001       150.5       2012-10-05  3005         5002
70009       270.65      2012-09-10  3001         5005
70002       65.26       2012-10-05  3002         5001
70004       110.5       2012-08-17  3009         5003
70007       948.5       2012-09-10  3005         5002
70005       2400.6      2012-07-27  3007         5001
70008       5760        2012-09-10  3002         5001
70010       1983.43     2012-10-10  3004         5006
70003       2480.4      2012-10-10  3009         5003
70012       250.45      2012-06-27  3008         5002
70011       75.29       2012-08-17  3003         5007
70013       3045.6      2012-04-25  3002         5001
Sql programming,
login and add your own answer to this question

All Answers

hamza
2022-05-18
need an explanation for this answer? contact us directly to get an explanation for this answer 

SELECT a.cust_name,a.city,a.grade, 
b.name AS "Salesman", 
c.ord_no, c.ord_date, c.purch_amt 
FROM customer a 
RIGHT OUTER JOIN salesman b 
ON b.salesman_id=a.salesman_id 
LEFT OUTER JOIN orders c 
ON c.customer_id=a.customer_id 
WHERE c.purch_amt>=2000 
AND a.grade IS NOT NULL;

Output of the Query:

cust_name	city		grade	Salesman	ord_no	ord_date	purch_amt
Nick Rimando	New York	100	James Hoog	70013	2012-04-25	3045.60
Nick Rimando	New York	100	James Hoog	70008	2012-09-10	5760.00
Brad Davis	New York	200	James Hoog	70005	2012-07-27	2400.60
Geoff Cameron	Berlin		100	Lauson Hen	70003	2012-10-10	2480.40

need an explanation for this answer? contact us directly to get an explanation for this answer

total answers (1)

Similar questions

need a help?

find thousands of online teachers now