Q:

Write a SQL statement to make a list in ascending order for the salesmen who works either for one or more customer or not yet join under any of the customers

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Write a SQL statement to make a list in ascending order for the salesmen who works either for one or more customer or not yet join under any of the customers.

Sample table: customer

customer_id |   cust_name    |    city    | grade | salesman_id 
-------------+----------------+------------+-------+-------------
        3002 | Nick Rimando   | New York   |   100 |        5001
        3007 | Brad Davis     | New York   |   200 |        5001
        3005 | Graham Zusi    | California |   200 |        5002
        3008 | Julian Green   | London     |   300 |        5002
        3004 | Fabian Johnson | Paris      |   300 |        5006
        3009 | Geoff Cameron  | Berlin     |   100 |        5003
        3003 | Jozy Altidor   | Moscow     |   200 |        5007
        3001 | Brad Guzan     | London     |       |        5005
 salesman_id |    name    |   city   | commission 
-------------+------------+----------+------------
        5001 | James Hoog | New York |       0.15
        5002 | Nail Knite | Paris    |       0.13
        5005 | Pit Alex   | London   |       0.11
        5006 | Mc Lyon    | Paris    |       0.14
        5007 | Paul Adam  | Rome     |       0.13
        5003 | Lauson Hen | San Jose |       0.12

 

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SELECT a.cust_name,a.city,a.grade, 
b.name AS "Salesman", b.city 
FROM customer a 
RIGHT OUTER JOIN salesman b 
ON b.salesman_id=a.salesman_id 
ORDER BY b.salesman_id;

Output of the Query:

cust_name	city		grade	Salesman	city
Brad Davis	New York	200	James Hoog	New York
Nick Rimando	New York	100	James Hoog	New York
Graham Zusi	California	200	Nail Knite	Paris
Julian Green	London		300	Nail Knite	Paris
Geoff Cameron	Berlin		100	Lauson Hen	San Jose
Brad Guzan	London			Pit Alex	London
Fabian Johnson	Paris		300	Mc Lyon		Paris
Jozy Altidor	Moscow		200	Paul Adam	Rome

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