Q:

From the following table, write a SQL query to count the unique orders, highest purchase amount for each customer

0

From the following table, write a SQL query to count the unique orders, highest purchase amount for each customer. Sort the result-set in descending order on 2nd field. Return customer ID, number of distinct orders and highest purchase amount by each customer.

Sample table: orders

ord_no      purch_amt   ord_date    customer_id  salesman_id
----------  ----------  ----------  -----------  -----------
70001       150.5       2012-10-05  3005         5002
70009       270.65      2012-09-10  3001         5005
70002       65.26       2012-10-05  3002         5001
70004       110.5       2012-08-17  3009         5003
70007       948.5       2012-09-10  3005         5002
70005       2400.6      2012-07-27  3007         5001
70008       5760        2012-09-10  3002         5001
70010       1983.43     2012-10-10  3004         5006
70003       2480.4      2012-10-10  3009         5003
70012       250.45      2012-06-27  3008         5002
70011       75.29       2012-08-17  3003         5007
70013       3045.6      2012-04-25  3002         5001

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SELECT customer_id, COUNT(DISTINCT ord_no), 
MAX(purch_amt) 
FROM orders 
GROUP BY customer_id 
ORDER BY 2 DESC;

Output of the Query:

customer_id	count		max
3002		3		5760.00
3009		2		2480.40
3005		2		948.50
3004		1		1983.43
3001		1		270.65
3007		1		2400.60
3008		1		250.45
3003		1		75.29

 

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