Let X be a continuous r.v has a p.f given by: f(x)={(ce^(-2x) , X≥0 0 otherwise)┤Find the value of c.

Since f(x) is a p.d.f, then ∫_(-∞)^∞〖f(x)〗 dx=1∴1=c∫_0^∞ e^(-2x) dx=c/2 [-e^(-2x) ]_0^∞=c/2c=2

total answers (1)

start bookmarking useful questions and collections and save it into your own study-lists, login now to start creating your own collections.

Since f(x) is a p.d.f, then ∫_(-∞)^∞〖f(x)〗 dx=1

need an explanation for this answer? contact us directly to get an explanation for this answer∴1=c∫_0^∞ e^(-2x) dx=c/2 [-e^(-2x) ]_0^∞=c/2

c=2