Let X be a r.v. has the probability function given by:

Find the value of the constant c.

Since∑〖xP(x)〗=E(X)Then(0.1)+2(0.3)+c+4(0.3)+5(0.1)=1But∑〖P(x)=1→∴0.1+0.3+c+0.3+0.1=1〗c=0.2

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Since

need an explanation for this answer? contact us directly to get an explanation for this answer∑〖xP(x)〗=E(X)

Then

(0.1)+2(0.3)+c+4(0.3)+5(0.1)=1

But

∑〖P(x)=1→∴0.1+0.3+c+0.3+0.1=1〗

c=0.2