Let X be a r.v. represents the life time of lamps which is produced by a factory and has a p.d.f given by:f(x)=ce^(-2x) , x>0Find the value of c.
Since f(x) is p.d.f, then ∫_(-∞)^∞ 〖f(x)〗 dx=1∴1=c∫_0^∞ e^(-2x) dx=c[-1/2 e^(-2x) ]_0^∞=1/2 c →c=2
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Since f(x) is p.d.f, then ∫_(-∞)^∞ 〖f(x)〗 dx=1
need an explanation for this answer? contact us directly to get an explanation for this answer∴1=c∫_0^∞ e^(-2x) dx=c[-1/2 e^(-2x) ]_0^∞=1/2 c →c=2