Let X be a r.v. has the probability function given by
Find the C.D.F
If X<1 ,then F(x)=0If 1≤X<2 ,then F(1)=P(1)=3⁄7If 2≤X<3 ,then F(2)=P(1)+P(2)=3⁄7+2⁄7=5⁄7If 3≤X<4 ,then F(3)=P(1)+P(2)+P(3)=6⁄7If 4≤X ,then F(4)=1Thus:F(x)={( 0 X<1 3⁄7 1≤X<2 ( 5)⁄7 2≤X<3 6⁄7 3≤X<4 1 4≤X )
total answers (1)
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If X<1 ,then F(x)=0
If 1≤X<2 ,then F(1)=P(1)=3⁄7
If 2≤X<3 ,then F(2)=P(1)+P(2)=3⁄7+2⁄7=5⁄7
If 3≤X<4 ,then F(3)=P(1)+P(2)+P(3)=6⁄7
If 4≤X ,then F(4)=1
Thus:
F(x)={( 0 X<1 3⁄7 1≤X<2 ( 5)⁄7 2≤X<3 6⁄7 3≤X<4 1 4≤X )
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