Suppose that the r.v X has the C.D.F given by:F(x)={( 2/5 x^2 0≤X<1 -3/5+2/5 (3x-1/2 x^2 ) 1≤X<2 1 X>2 )┤Find the P.d.f

Since:f(x)=(dF(x))/dxThus:f(x)={( 4/5 x 0<X≤1 2/5 (3-x) 1<X≤2 0 otherwise )┤

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Since:

need an explanation for this answer? contact us directly to get an explanation for this answerf(x)=(dF(x))/dx

Thus:

f(x)={( 4/5 x 0<X≤1 2/5 (3-x) 1<X≤2 0 otherwise )┤