Q:

The law of logarithm states that 1/(log_x⁡a)=log_a⁡x also, log_a⁡a=1 Find the value of: 1/(log_3⁡12)=log_12⁡3

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The law of logarithm states that 1/(log_x⁡a)=log_a⁡x also, log_a⁡a=1  Find the value of: 1/(log_3⁡12)=log_12⁡3

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Step 1 of 2

Find the value of:

1/(log_3⁡12)=log_12⁡3

1/(log_4⁡12)=log_12⁡4

Step 2 of 2

Calculate the value of (1/(log_3⁡12)+1/(log_4⁡12))

⇒log_12⁡3+log_12⁡4=log_12⁡3×4

⇒log_12⁡12

⇒1

Hence the value of (1/(log_3⁡12)+1/(log_4⁡12)) is 1

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