Given P(A)=0.5 ,P(B)=0.3 , P(A∪B)=0.63Evaluate P(A^c∩B^c )
∵P(A∪B)=P(A)+P(B)-P(A∩B) ∴P(A∩B)=P(A)+P(B)-P(A∪B) =0.5+0.3-0.63=0.17P(A^c∩B^c )=P(A∪B)^c=1-P(A∪B) =1-0.63=0.37
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∵P(A∪B)=P(A)+P(B)-P(A∩B)
need an explanation for this answer? contact us directly to get an explanation for this answer∴P(A∩B)=P(A)+P(B)-P(A∪B)
=0.5+0.3-0.63=0.17
P(A^c∩B^c )=P(A∪B)^c=1-P(A∪B)
=1-0.63=0.37