Given the three event A,B and C which are partitioned of the sample space such thatP(A)=3/4 ,P(B)=3P(C)Find P(B)

Since the three events are partitioned then:P(A)+P(B)+P(C)=1∴ 3/4 P(A)+P(B)+3/12 P(B)=1∴ 2 P(B)=1→P(B)=1/2 And P(A)=3/4 (1/2)=3/8 ,P(C)=1/4 (1/2)=1/8

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Since the three events are partitioned then:

need an explanation for this answer? contact us directly to get an explanation for this answerP(A)+P(B)+P(C)=1

∴ 3/4 P(A)+P(B)+3/12 P(B)=1

∴ 2 P(B)=1→P(B)=1/2

And P(A)=3/4 (1/2)=3/8 ,P(C)=1/4 (1/2)=1/8