K_1={drawing an ace in the first draw} K_2={drawing an ace in the second draw} K_3={drawing an ace in the third draw} K_4={drawing an ace in the fourth draw} K_1,K_2,K_3,K_4 are independent P(K_1∩K_2∩K_3∩K_4 )=P(K_1 ).P(K_2 ).P(K_3 ).P(K_4 )=4/52*4/52*4/52*4/52
K_1={drawing an ace in the first draw}
need an explanation for this answer? contact us directly to get an explanation for this answerK_2={drawing an ace in the second draw}
K_3={drawing an ace in the third draw}
K_4={drawing an ace in the fourth draw}
K_1,K_2,K_3,K_4 are independent
P(K_1∩K_2∩K_3∩K_4 )=P(K_1 ).P(K_2 ).P(K_3 ).P(K_4 )=4/52*4/52*4/52*4/52