In experiment of tossing a coin three times. Find probability appear tail at each of the first two tosses.

n(S)=(2)^3=8S={HHH,HHT,HTH,HTT,THH,TTH,THT,TTT}A={event appear tail at each of the first two tosses}A={HTH,HTT,THH,THT,TTH,TTT}P(A)=(n(A))/(n(S))=6/8=3/4

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n(S)=(2)^3=8

need an explanation for this answer? contact us directly to get an explanation for this answerS={HHH,HHT,HTH,HTT,THH,TTH,THT,TTT}

A={event appear tail at each of the first two tosses}

A={HTH,HTT,THH,THT,TTH,TTT}

P(A)=(n(A))/(n(S))=6/8=3/4