Fair die loaded in way even number appear is twice likely than odd number. Find probability appear prime number if die tossed once.
S={1,2,3,4,5,6}A={event appear prime number}A={2,3,5}∵P(1)=P(3)=P(5)=w∴P(2)=P(4)=P(6)=2w∵P(1)+P(2)+P(3)+P(4)+P(5)+P(6)=1∴3w+3(2w)=1 ,9w=1 ,w=1/9∴P(A)=P(2)+P(3)+P(5)=2/9+1/9+1/9=4/9
total answers (1)
start bookmarking useful questions and collections and save it into your own study-lists, login now to start creating your own collections.
S={1,2,3,4,5,6}
need an explanation for this answer? contact us directly to get an explanation for this answerA={event appear prime number}
A={2,3,5}
∵P(1)=P(3)=P(5)=w
∴P(2)=P(4)=P(6)=2w
∵P(1)+P(2)+P(3)+P(4)+P(5)+P(6)=1
∴3w+3(2w)=1 ,9w=1 ,w=1/9
∴P(A)=P(2)+P(3)+P(5)=2/9+1/9+1/9=4/9