Fair die loaded in way even number appear is twice likely than odd number. Find probability appear prime number if die tossed once.

S={1,2,3,4,5,6}A={event appear prime number}A={2,3,5}∵P(1)=P(3)=P(5)=w∴P(2)=P(4)=P(6)=2w∵P(1)+P(2)+P(3)+P(4)+P(5)+P(6)=1∴3w+3(2w)=1 ,9w=1 ,w=1/9∴P(A)=P(2)+P(3)+P(5)=2/9+1/9+1/9=4/9

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S={1,2,3,4,5,6}

need an explanation for this answer? contact us directly to get an explanation for this answerA={event appear prime number}

A={2,3,5}

∵P(1)=P(3)=P(5)=w

∴P(2)=P(4)=P(6)=2w

∵P(1)+P(2)+P(3)+P(4)+P(5)+P(6)=1

∴3w+3(2w)=1 ,9w=1 ,w=1/9

∴P(A)=P(2)+P(3)+P(5)=2/9+1/9+1/9=4/9