solve ((d^2 y)/(dx^2 )-2 dy/dx+y)=cos 3x
The A.E. is m^2-2m+1=0 Or (m-1)^2=0so m=1,1Y_(C.F.)=(c_1+c_2 x) e^xY_(P.I.)=1/(D^2-2D+1) cos3x=1/(-9-2D+1) cos3x =-1/2 1/(D+4) cos3x=-1/2 (D-4)/(D^2-16) cos3x=-1/2 (D-4)/(-9-16) cos3x =1/50 (-3 sin3x-4 cos3x )=-1/50 (3 sin3x+4 cos3x )Y_(G.S.)=(c_1+c_2 x) e^x-1/50 (3 sin3x+4 cos3x )
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The A.E. is m^2-2m+1=0
need an explanation for this answer? contact us directly to get an explanation for this answerOr (m-1)^2=0
so m=1,1
Y_(C.F.)=(c_1+c_2 x) e^x
Y_(P.I.)=1/(D^2-2D+1) cos3x=1/(-9-2D+1) cos3x
=-1/2 1/(D+4) cos3x=-1/2 (D-4)/(D^2-16) cos3x=-1/2 (D-4)/(-9-16) cos3x
=1/50 (-3 sin3x-4 cos3x )=-1/50 (3 sin3x+4 cos3x )
Y_(G.S.)=(c_1+c_2 x) e^x-1/50 (3 sin3x+4 cos3x )