solve the following equation y^''+6y^'+4y=0

hamza

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2022-05-18

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Mathematics,

hamza

2022-05-18

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Here A.E. is m^2+6m+4=0
givening m=-3±√5
Hence the general solution is:
Y_(G.S.)=e^(-3x) (c_1 cosh⁡〖(x√5〗)+c_2 sinh⁡〖(x√5)〗 )

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