Evaluate the following integral I=∫_0^(π⁄2)(〖sin〗^n x)/(〖sin〗^n x+〖cos〗^n x) dx
Evaluate I=∫_0^(π⁄2)(〖sin〗^n x)/(〖sin〗^n x+〖cos〗^n x) dx →(1)Since I=∫_0^(π⁄2)(〖sin〗^n (π/2-x))/(〖sin〗^n (π/2-x)+〖cos〗^n (π/2-x) ) dx =∫_0^(π⁄2)(〖cos〗^n x)/(〖cos〗^n x+〖sin〗^n x) dx →(2)Adding (1) and (2) we get:2I=∫_0^(π⁄2)(〖cos〗^n x+〖sin〗^n x)/(〖cos〗^n x+〖sin〗^n x) dx=∫_0^(π⁄2)dx=π⁄2 →∴I=π/4
total answers (1)
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Evaluate I=∫_0^(π⁄2)(〖sin〗^n x)/(〖sin〗^n x+〖cos〗^n x) dx →(1)
need an explanation for this answer? contact us directly to get an explanation for this answerSince I=∫_0^(π⁄2)(〖sin〗^n (π/2-x))/(〖sin〗^n (π/2-x)+〖cos〗^n (π/2-x) ) dx
=∫_0^(π⁄2)(〖cos〗^n x)/(〖cos〗^n x+〖sin〗^n x) dx →(2)
Adding (1) and (2) we get:
2I=∫_0^(π⁄2)(〖cos〗^n x+〖sin〗^n x)/(〖cos〗^n x+〖sin〗^n x) dx=∫_0^(π⁄2)dx=π⁄2 →∴I=π/4