Q:

Evaluate the following integral I=∫_0^π〖〖cos〗^6 x〗 dx

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Evaluate the following integral I=∫_0^π〖〖cos〗^6 x〗 dx  

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Since  〖cos〗^6 (π-x)
∴∫_0^π〖〖cos〗^6 x〗 dx =2∫_0^(π⁄2)〖〖cos〗^6 x〗 dx  =2.5.3.1/6.4.2.π/2=5π/16 

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