Evaluate the following integral ∫_a^blnx/x dx
∫_a^blnx/x dx let u=lnx→du=dx/x ∴x=a→u=lna,x=b→u=lnb∴I=∫_lna^lnbu du=├ 1/2 u^2 ┤|_lna^lnb = 1/2 [(lnb )^2-(lna )^2 ]=1/2 [(lnb-lna )(lna+lnb ]=1/2 ln(b/a) ln(ab)
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∫_a^blnx/x dx let u=lnx→du=dx/x
need an explanation for this answer? contact us directly to get an explanation for this answer∴x=a→u=lna,x=b→u=lnb
∴I=∫_lna^lnbu du=├ 1/2 u^2 ┤|_lna^lnb = 1/2 [(lnb )^2-(lna )^2 ]
=1/2 [(lnb-lna )(lna+lnb ]=1/2 ln(b/a) ln(ab)